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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Text Table with sorting
 I am trying to generate a style sheet that will generate text output. The output must be formatted in a text table. I have been able to generate the table for most elements, but there is a set of three elements that must appear on the same row, and they must be sorted by the refDate attribute. Because this is output as text, I must print the table line by line, instead of column by column. I have accomplished this by first figuring out what column has the most entries (in the example below this would be maritalStatus). Then I do a for-each on that column, and print out each entry by indexing the three node-sets. The problem is, since I am doing only one for-each loop I can't seem to sort multiple columns. Here is an example... XML---- <person> <maritalStatus refDate="1993-06-24">divorce</maritalStatus> <maritalStatus refDate="1997-01-15">marriage</maritalStatus> <maritalStatus refDate="1989-04-11">marriage</maritalStatus> <dateOfBirth>1968-04-05</dateOfBirth> <religion refDate="1968-04-05">Roman Catholic</religion> <religion refDate="1996-12-02">Lutheran</religion> </person> Output---- Marital Status Date of Birth Religion marriage (1997-01-15) 1968-04-05 Lutheran (1996-12-02) divorce (1993-06-24) Roman Catholic (1968-04-05) marriage (1989-04-11) So my style sheet right now looks something like this... I first figure out what column has the most elements, in this case the left column so I say... <xsl:for-each select="$left"> <xsl:variable name="for-each-pos" select="position()" /> <xsl:call-template name="print-entry">
<xsl:with-param name="entry" select="$left[ $for-each-pos ]"/>
</xsl:call-template> <xsl:call-template name="print-entry">
<xsl:with-param name="entry" select="$middle[ $for-each-pos ]"/>
</xsl:call-template> <xsl:call-template name="print-entry">
<xsl:with-param name="entry" select="$right[ $for-each-pos ]"/>
</xsl:call-template><xsl:text> </xsl:text> </xsl:for-each> The parameters left, middle, and right are node-sets of all the person/maritalStatus, person/dateOfBirth, and person/religion elements, respectively. I can't figure out how to sort the right column when I am doing a for-each on the left column. Does anyone know how I could do that? Can I fit a <xsl:sort> into my currect structure somehow, or would I need to redo how I print the tables? It seems as though I would have to sort the right column node-set before I enter the for-each loop, but I don't know that is possible in XSLT, because <xsl:sort> doesn't actually sort the set, it just traverses the set in a sorted order, right? Any help is greatly appreciated. Thanks --Ryan XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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