RE: How to use two xmls for comparing and extracting v

Hi Dipesh,
  Your problem description seems a bit ambiguous to
me. Hope you can explain more clearly.. To my best
understanding, you need an XSL like below --

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" version="1.0"
encoding="UTF-8" indent="yes"/>
	
<xsl:variable name="Schema"
select="document('colHeader.xml')"/>
   <xsl:template match="/">
     <xsl:variable name="x"
select="Table/Column[1]/@name" />   
     <xsl:variable name="y"
select="Table/Column[2]/@name" />          
     <xsl:for-each select="$Schema/Root/@*">
       <xsl:if test="name(.) = $x">
         `<xsl:value-of select="." />
       </xsl:if>
       <xsl:if test="name(.) = $y">
         `<xsl:value-of select="." />
       </xsl:if>
     </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

The colHeader.xml file will contain --
<?xml version="1.0" encoding="UTF-8"?>
<Root att1="val1" and att2="val2" />

And, the XML file, to which you will apply the above
XSL will contain --
<?xml version="1.0" encoding="UTF-8"?>
<Table Name="Root">
  <Column name="att1"/>
  <Column name="att2"/>
</Table>


Regards,
Mukul


--- Dipesh Khakhkhar <dkhakhkh@xxxxxxxxxxxxxxx> wrote:
> Hi,
> 
> First of all thanks for replying.
> 
> I am extremely sorry for writing incorrect desired
> output.
> Actually i would like to have output like
> `val1'val2
> 
> I am having input file having node like this
> <Root att1="val1" and att2="val2".
> 
> I am having the intermediate file which i
> constructed from input file havin 
> structure.
> 
> <Table Name="Root">
> <Column name="att1"/>
> <Column name="att2"/>
> 
> Now i would like to have output like
> `val1`val2
> 
> <xsl:variable name="Schema"
> select="document('colHeader.xml')"/>
> 
> In the Schema variable I am having the document root
> of the intermediate file.
> 
> I am trying to compare name of the attribute of the
> Root node  against the 
> value of the Column's naame attribute and if they
> are equal then outputting 
> the value of the attribute of the Root node.
> 
> I guess I have not confused with the above
> statement.
> 
> Sorry once again for giving incorrect output
> information.
> 
> Eagerly waiting for reply.
> 
> Regards,
> Dipesh
> 
> 
> 
> 
> Date: Thu, 11 Sep 2003 09:06:03 +0300
> From: Jarno.Elovirta@xxxxxxxxx
> Subject: RE:  How to use two xmls for comparing
> and extracting values
> 
> Hi,
> 
> > If I have a node like this in my original xml.
> >
> > <Root att1="val1" att2="val2">
> >
> > and the intermediate xml has node like this
> > <Table name="Root">
> > <Column name="att1"/>
> > <Column name="att2"/>
> > </Table>
> >
> > I want to output values like
> > att1`att2.
> 
> If you wanted to use the original source directly,
> it's
> 
> <xsl:for-each select="Root/@*">
> <xsl:sort select="translate(name(),
> translate(name(), '0123456789', ''), '')" 
> data-type="number"/>
> <xsl:if test="not(position() = 1)">`</xsl:if>
> <xsl:value-of select="name()"/>
> </xsl:for-each>
> <xsl:text>.</xsl:text>
> 
> and for the intermediate
> 
> <xsl:for-each select="Table/Column">
> <xsl:if test="not(position() = 1)">`</xsl:if>
> <xsl:value-of select="@name"/>
> </xsl:for-each>
> <xsl:text>.</xsl:text>
> 
> Cheers,
> 
> Jarno - Hypnoskull: Biotech Brainkillers
> (Deconstructed)
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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