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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to modify img and href in an xhtml document
 Use the identity transformation (your second solution) and override it with the templates you have for specific elements -- e.g. img and a. This means to place your specific templates after the identity template. ===== Cheers, Dimitre Novatchev. http://fxsl.sourceforge.net/ -- the home of FXSL "Terje Christensen" <terchris@xxxxxxxxxxx> wrote in message news:Law10-F16gRLNTaFagA00010532@xxxxxxxxxxxxxx I have a xml structure. Within that structure there is an html document (/page/document/html/body) I want to change the img and href tags inside /page/document/html/body in order to make the links work properly. I also need to remove a header and footer from the html document. The XML input file looks like this: <body> <div class="theDocumentHeaderNavBars"> . . . Some tables that must be deleted . . . </div> <div> . . . this is the html document . . . </div> <div class="theDocumentFooterNavBars"> . . . Some tables that must be deleted . . . </div> I have written templates: for img and a tags. They are similar so I just put the img template here: <xsl:template match="img"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:attribute name="src"> <xsl:choose> <xsl:when test="starts-with(@src,'./')"> <!-- if 'src' attribute has relative value --> <xsl:value-of select="concat(/page/@dataRelRoot,/page/currentItem/@itemFullPath,substring( @src,2))"/> </xsl:when> <xsl:when test="starts-with(@src,'http://')"> <!-- if 'src' attribute has absolute value --> <xsl:value-of select="@src"/> </xsl:when> <xsl:otherwise> <xsl:value-of select="concat(/page/@dataRelRoot,/page/currentItem/@itemFullPath,'/',@src)" /> </xsl:otherwise> </xsl:choose> </xsl:attribute> <xsl:apply-templates/> </xsl:copy> </xsl:template> The img template works, and replaces the src attribute. I have written a template for the div tag. I'm just printing a text when top and footer div tags are processed. <xsl:template match="div"> <xsl:choose> <xsl:when test="@class = 'theDocumentHeaderNavBars' or @class = 'theDocumentFooterNavBars' ">drop the Top or Bottom headers </xsl:when> <xsl:otherwise> <xsl:copy> <xsl:copy-of select="."/> <!-- <xsl:apply-templates select="node()|@*|processing-instruction()"/> --> </xsl:copy> </xsl:otherwise> </xsl:choose> </xsl:template> But, how to start the transformation? I have tried to start the transformation, but I do not get the result I want. <!-- this creates rubbish - just copies the text no tags for tables and so on <xsl:template match="/page/document/html/body"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> --> <!-- This works, but it process the whole xml input file. And is it fast enough? <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> --> I hope that you can help me with a basic xslt question. Thanks Terje Chr. _________________________________________________________________ Hotmail snakker ditt språk! http://www.hotmail.msn.com/cgi-bin/sbox?rru=dasp/lang.asp - Få Hotmail på norsk i dag XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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