RE: Date Format in XSLT

If the names are all three characters, use

substring("JanFebMarApr....", ($month-1)*3+1, 3)

Michael Kay

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> michel geadah
> Sent: 04 September 2003 13:47
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Date Format in XSLT
> 
> 
> hi,
> 
> I need to transform the month to words.
> For example, if i have '1' i need to output 'Jan', if i have 
> '2' i need to 
> output 'Feb', and so on...
> (That is to say if i have 1-12-2003 i need it to be transformed to 
> 1-Dec-2003)
> 
> Thanks...
> Michel
> 
> _________________________________________________________________
> Tired of spam? Get advanced junk mail protection with MSN 8. 
> http://join.msn.com/?page=features/junkmail
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list