Re: limit count() to nodes with a position() < the

Thank you Micheal.  This was my one last remaining piece of the puzzle!

Best Regards,

M.


----- Original Message ----- 
From: "Michael Kay" <mhk@xxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, September 09, 2003 2:30 AM
Subject: RE:  limit count() to nodes with a position() &lt; the postion 
of the current node


> > But I want to take this one step further and return the count
> > of all nodes
> > that have a position() that is less than the position of the
> > current node.
> > Taking the position() of the context node out of the equation
> > I thought it
> > would as simple as this (I used 5 as a test parameter)...
>
> Nodes do not "have a position()". The result of the position() function
> is context dependent: it returns the position of the current node in the
> current node list, and the current node list depends on how you reached
> the node in your processing.
>
> I suspect that you are using "the position of a node" to mean something
> like "the number of preceding siblings of the node", which is
> count(preceding-sibling::node()).
>
> Michael Kay
>
>
> >
> > <xsl:key name="linkCount" match="lid[position() &lt; 5]" use="."/>
> >
> > I expected it to return the count of the nodes that matched
> > the current
> > context node as long as there postion was less than 5.  But
> > it didn't.  It
> > returned the total count for the entire xml tree.
> >
> > So, my questions are...  1)What do I need to change to get
> > the above example
> > to work and 2)How could I then take it one step further and use the
> > position() of the current context node as the parameter to
> > test against the
> > position() of the test nodes?
> >
> > Your help is much appreciated!
> >
> > Best Regards,
> >
> > M.David
> >
> >  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> >
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
> 

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