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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Group and sort by group element occurrences
Please try the XSL below --
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xalan="http://xml.apache.org/xalan"
exclude-result-prefixes="xalan">
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:key name="x" match="docroot/token/pageid"
use="."/>
<xsl:template match="/">
<xsl:variable name="treefrag">
<docroot>
<xsl:for-each select="docroot/token/pageid">
<xsl:if test="generate-id(.) =
generate-id(key('x', .)[1])">
<page>
<pageid>
<xsl:value-of select="."/>
</pageid>
<no_of_times>
<xsl:value-of select="count(key('x', .))"/>
</no_of_times>
</page>
</xsl:if>
</xsl:for-each>
</docroot>
</xsl:variable>
<xsl:call-template name="process_tree">
<xsl:with-param name="tree"
select="xalan:nodeset($treefrag)"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="process_tree">
<xsl:param name="tree"/>
<docroot>
<xsl:for-each select="$tree/docroot/page">
<xsl:sort select="no_of_times" data-type="number"
order="descending"/>
<pageid>
<xsl:value-of select="pageid"/>
</pageid>
</xsl:for-each>
</docroot>
</xsl:template>
</xsl:stylesheet>
We need to use Muenchian method for grouping. I have
used xalan:nodeset extension function. Jarno's
solution looks simpler..
Regards,
Mukul
--- "Simerman, Joshua Michael" <jsimerma@xxxxxxxxxxx>
wrote:
> Long time reader, first time poster.
>
> I have an xml doc that is the result of a keyword
> search, which list the
> keyword, and all pages by id that have that instance
> of the keyword. The
> output looks like this.
>
> <?xml version="1.0" encoding="UTF-8"?>
> <docroot>
> <token>apply
> <pageid>1</pageid>
> <pageid>3</pageid>
> <pageid>84</pageid>
> </token>
> <token>international
> <pageid>3</pageid>
> <pageid>5</pageid>
> <pageid>84</pageid>
> </token>
> <token>financial aid
> <pageid>5</pageid>
> <pageid>84</pageid>
> </token>
> </docroot>
>
> I need to transform this this into a grouped and
> sorted list of page
> id's, so that the instances of pageid that occur the
> most frequently are
> first, and so that each pageid is listed only once.
> The above xml would
> then look like this.
>
> <docroot>
> <pageid>84</pageid>
> <pageid>3</pageid>
> <pageid>5</pageid>
> <pageid>1</pageid>
> </docroot>
>
> It seems like a fairly simple transform, but I just
> cant get it to sort
> properly and then have only the unique page ids. I
> just end up with a
> flat list of the original document, or nothing at
> all.
>
> Thanks,
>
> Josh Simerman
> Graduate Assistant, Web Developer
> Systems & Accounting Graduate Programs
> Indiana University, Kelley School of Business
>
>
> XSL-List info and archive:
> http://www.mulberrytech.com/xsl/xsl-list
>
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