Re: Problem with Parameter binding with String

It seems like you can only use the parameter(variable)
in the predicates with XPATH.

So, I can do this:


<xsl:copy-of select="*[name(.) = $pName]"/>


To copy the orignal element to the output.


Thanks

Dongling

--- Dongling Ding <dling61@xxxxxxxxx> wrote:
> 
> Hi,
> 
> 
> I am trying again here. Hope someone can help me on
> this.
> 
> I have a test.xml and a name list in another xml
> file
> called lookup.xml. I open the test.xml and also look
> at the lookup.xml to see if there is any element
> missing in the test.xml. If exists, I can just copy
> the element into the result tree; if not, i can
> create
> that one.
> 
> A template can do this job like:
> 
> 
> <xsl:call-template name="replacement">
> <xsl:with-param name="pName" select="'XX'"/>
> <xsl:with-param name="defaultValue" select="'+'"/>
> </xsl:call-template>
> 
> 
> 
> <xsl:template name="replacement">
> 	<xsl:param name="pName"/>
> 	<xsl:param name="defaultValue"/>	
> 	<xsl:choose>
> 	  <xsl:when test="*[name(.) = $pName]">		
> <xsl:copy-of select="?????"/>
> 	  </xsl:when>
> 	  <xsl:otherwise>
> 		<xsl:element name="{$pName}">
> 		<xsl:value-of select="$defaultValue"/>
> 		</xsl:element>
> 	  </xsl:otherwise>
> 	</xsl:choose>
> </xsl:template>
> 
> test.xml:
> 
> <Member>
>   <XX>1</XX>
> </Member>
> 
> 
> I have to call the template replacement and pass the
> pName as string since that is the thing I got from
> lookup.xml. But in the template I just can NOT copy
> that XX element and value because the pName is a
> string. Is this the same problem like converting a
> string into node-set? Or is there any workaround for
> this.
> 
> 
> Thanks
> 
> 
> Dongling
> 
> 
> 
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