Re: Display value AND apply templates

Try this

<xsl:template match="/">
    <xsl:apply-templates />
</xsl:template>

<xsl:template match="para">
    <p>
        <xsl:apply-templates />
    </p>
</xsl:template>

<xsl:template match="chem">
    <span class="chem>
        <xsl:apply-templates />
    </chem>
</xsl:template>

<xsl:template match="sub">
    <sub>
        <xsl:apply-templates />
    </sub>
</xsl:template>

<xsl:template match="text()">
    <xsl:value-of select="." />
</xsl:template>

----- Original Message ----- 
From: "Drew McLellan" <dru@xxxxxxxxxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, August 11, 2003 1:45 PM
Subject:  Display value AND apply templates


> I've been looking at this for too long and can no longer think clearly.
Take this example:
>
> <myxml>
>     <para>The notation for water is
>         <chem>H
>             <sub>2</sub>
>         0
>         </chem>
>     </para>
> </myxml>
>
> I'm trying to transform to XHTML. The desired output for the above would
be:
>
> <p>The notation for water is <span class="chem">H<sub>2</sub>0</span></p>
>
> The problem I have is that if I use value-of "." I can get the value of
node, but no further templates are applied. If I use apply-templates "*" I
get the sub-templates but no value.
>
> For example:
>
> <xsl:template match="chem">
>     <span class="chem"><xsl:apply-template select="*" /></span>
> </xsl:template>
>
> <xsl:template match="sub">
>     <sub><xsl:value-of select="." /></sub>
> </xsl:template>
>
> This gets the <sub> but loses the value of the <chem>.
>
> As I say, I've lost all clarity of mind on this, so I'm expecting it to be
obvious! Any and all suggestions most welcome.
>
> Thanks for your time.
>
> Drew McLellan
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list