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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] how to set the bgcolor of a table cell to the value of
 Hi everyone,
each stock has it's own row and each cell represents
a trading day. i'm trying to set the bgcolor of each
cell to the color(in hex) for that particular node. my
knowledge of XSLT is quite limited and i have no idea
how to do this. i've attached both the xslt file and a
snippet of the xslt file. i'm using Xalan and Xerces
thru JAXP. pls help!
thanks....Zain
here is a sample of my XML file....
<Equities-List>
<Equity name="CP">
<EquityNode date="2000-01-03" close="9.6">
<Color hex="246f15">
</EquityNode>
<EquityNode date="2000-01-04" close="9.7">
<Color hex="227017">
</EquityNode>
<EquityNode date="2000-01-05" close="9.9">
<Color hex="1f731a">
</EquityNode>
</Equity>
</Equities-List>
and here's my XSLT file....
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="//Equity">
<tr>
<td>
<xsl:value-of select="@name">
</td>
<td>
<xsl:apply-templates select="EquityNode"/>
</td>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
<xsl:template match=EquityNode">
<td bgcolor="<!-- SET COLOR TO @HEX IN COLOR NODE
-->">
<xsl:value-of select="@date"/>
<xsl:text> close= </xsl:text>
<xsl:value-of select="@close"/>
<br/><br/>
<xsl:apply-templates select="Color"/>
</td>
</xsl:template>
<xsl:template match=Color">
<xsl:text> Hex= </xsl:text>
<xsl:value-of select="@hex"/>
</xsl:template>
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