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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] sort and order xml data according to what user selects
 I want to be able to sort and order my XML data according to what the user
selects from a form.
I am quite a novice to XSL and haven't worked with forms that much at all.
So, when the user selects "size" from the menu, the XML data would be sorted
by "size"
and when the user selects the ascending radio button, I want the XML data
order by "ascending"
How would I acomplish this?
here is the code that I have:
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<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html><body>
<form id="form" method="post" action="">
Sort by:
<select id="sortby">
<option selected="selected">title</option>
<option>author</option>
<option>date</option>
<option>citation</option>
<option>pages</option>
<option>size</option>
</select>
Order of:
<input id="descending" name="sortorder" type="radio" value="descending"
checked="checked" />
<label for="descending">Descending</label>
<input id="ascending" name="sortorder" type="radio" value="ascending" />
<label for="ascending">Ascending</label>
</form>
<xsl:for-each select="catalog/publication">
<xsl:sort select="date" order="descending" />
...
here where the xml data is displayed
...
</xsl:for-each>
</body></html>
</xsl:template>
</xsl:stylesheet>
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