Re: Strange Problem with document($variablename)

Jeni,

<xsl:variable name="filename"
              select="concat('../content/news/', @name)" />

Thank you. That at least make the code more efficient. I had overlooked
that.

>> I doubt that it will give you a different result.

Right. It doesn't.

>> the reason that the file isn't found might be because the
>> URL is being resolved relative to the directory that the stylesheet
>> lives in rather than the directory that the XML document lives in. Try
>> using:

It is. This is why I need to prefix this with ../ to get out of the
stylesheets directory. Again, thank you for the hint, 

>>  document($filename, .)

is again much more elegant.

BUT this does not touch the original problem. It is the *path* at which the
file is being sought. The actual filename piece is lost somewhere, but
*only*
if the concatenated pathname starts with anything else than either the /
character or an alphanumeric character. If it is trying to open the file
"../content/news" instead of "../content/news/foo.html" it is not going to
find it.

I look as if something in between the stylesheet and the actual file system
call is trying to interpret the path against anyhting and gets this wrong. I
need to admin I am running this in Cocoon. Might cocoon be fooling me here?
How would I be able to debug this?

Torsten

> Hi Torsten,
> 
> > Using <p><xsl:value-of select="$filename"/></p> the correct filename
> > is being printed.
> >
> > (For example ../content/news/foo" if @name == foo.)
> >
> > Using document($filename) I get a java.io.FileNotFound exception for
> > "../content/news/" (where is the foo gone; it the identical
> > variable!!!).
> 
> That's very peculiar. If you want an equivalent variable, try using
> the concat() function:
> 
> <xsl:variable name="filename"
>               select="concat('../content/news/', @name)" />
> 
> I doubt that it will give you a different result.
> 
> By the way, the reason that the file isn't found might be because the
> URL is being resolved relative to the directory that the stylesheet
> lives in rather than the directory that the XML document lives in. Try
> using:
> 
>   document($filename, .)
> 
> to get the $filename URL to be resolved relative to the current
> <directory> element.
> 
> Cheers,
> 
> Jeni
> 
> ---
> Jeni Tennison
> http://www.jenitennison.com/
> 




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list