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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Nodes between two nodes with the same name (again :-(
I need to output all nodes between two nodes with the same name, so that
from the node <h> becomes the HEADER and all nodes after <h> until the next
<h> become the BODY. The source file is:
<html>
<body>
<h> Header </h>
<p> A </p>
<dl>
<dt> B </dt>
<dt> C </dt>
</dl>
<h>Header </h>
<p> D </p>
<dl>
<dt>
<dt> E </dt>
</dt>
</dl>
<p> F </p>
</body>
</html>
I need to have this output
<ROWSET>
<ROW>
<HEADER> Header </HEADER>
<BODY> ABC </BODY>
</ROW>
<ROW>
<HEADER> Header </HEADER>
<BODY> DEF </BODY>
</ROW>
<ROWSET>
I found the similar posting on xsl list at
http://www.biglist.com/lists/xsl-list/archives/20008/msg01102.html
by Jeni Tennison by have hard time implementing it. My xsl is
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="html/body">
<ROWSET>
<xsl:apply-templates/>
</ROWSET>
</xsl:template>
<xsl:template match="html/body/h">
<ROW>
<HEADER>
<xsl:value-of select="."/>
</HEADER>
<BODY>
<xsl:apply-templates
select="following-sibling::*[generate-id(following-sibling::html/body/h[1])=
generate-id(current()/following-sibling::html/body/h[1])]"/>
</BODY>
</ROW>
</xsl:template>
</xsl:stylesheet>
and it gives me (numbers for reference only):
1 <ROWSET>
2 <ROW>
3 <HEADER> Header </HEADER>
4 <BODY> ABC
5 <ROW>
6 <HEADER> Header </HEADER>
7 <BODY> DEF </BODY>
8 </ROW>
9 DEF
10 </BODY>
11 </ROW>
12 ABC
13 <ROW>
14 <HEADER> Header </HEADER>
15 <BODY> DEF </BODY>
16 </ROW>
17 DEF
18 <ROWSET>
with lines 5-9,12,17 that I don't want to be there.
Please, can someone help.
Thank you.
Anatoliy Smirnov
Department of Veterans Affairs
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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