Cart
|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Replacing many attributes
 more efficient way of doing this. I am currently doing this below but there must be a better way. <xsl:template match="para/@meta[.='cc_gen_desc']"> <xsl:attribute name="meta">description</xsl:attribute> </xsl:template> <xsl:template match="para/@meta[.='cc_life_contrib_entity']"> <xsl:attribute name="meta">entity</xsl:attribute> </xsl:template> <xsl:template match="para/@meta[.='cc_life_contrib_date']"> <xsl:attribute name="meta">date</xsl:attribute> </xsl:template> <xsl:template match="para/@meta[.='cc_tech_format']"> <xsl:attribute name="meta">format</xsl:attribute> </xsl:template> <xsl:template match="para/@meta[.='cc_tech_duration']"> <xsl:attribute name="meta">duration</xsl:attribute> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! 
Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|
