Re: xsd:import and namespaces

To access the value of schemaLocation,
use the following expression:

<xsl:variable name="schema" select="../xsd:import/@schemaLocation"/>

regards,
sundar

-----Original Message-----
From: Peter Moore [mailto:pmoore@xxxxxxx]
Sent: Thursday, April 24, 2003 3:39 AM
To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
Subject:  xsd:import and namespaces

How can I get the value of schemaLocation from the xsd:element/@ref
attribute in the following XML Schema sample:

...
<xsd:schema ... xmlns:xxx="http://www.yo.com/example.namespace">
<xsd:import namespace="http://www.yo.com/example.namespace"
schemaLocation="http://www.yo.com/example.xsd"/>
...
<xsd:element ref="xxx:SomeName"/>
...

My xsl looks something like this:

...
<xsl:template match="xsd:element[@ref]">
	<xsl:element name="{@ref}">
		<xsl:variable name="schema"
select="//xsd:import/@schemaLocation[../@namespace=???]"/>

		<xsl:apply-templates
select="document($schema)//element[@name=current()/@ref]"/>
	</xsl:element>
</xsl:template>
...

Am I on the right track? If so, what should replace the ??? in the
location path? If I remove the stuff between the xsl:element tags I get
the following output:

...
	<xxx:SomeName xmlns:xxx="http://www.yo.com/example.namespace"/>
...

So XSLT knows the namespace I want...I just don't know how to ask it.

Thanks.

BTW...I'm using LibXSLT and perl for the transform.


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