RE: Variable select="concat()" not loading variable.

> 
> I am trying to concatinate a collection of text() strings 
> (see xsl below) however the variable (timestamps)  is not 
> being filled with any data.  Could someone tell me why?  The 
> total number of timestamps to be concatinated is 10,000.

You are trying to assign to a variable. Basic error - that's not how
variables in XSLT work. It's not a procedural language like JavaScript.
Read any number of posts about variable assignment, procedural vs
declarative programming, etc, or any XSLT textbook.

You want something like:

<xsl:variable name="timespamps">
  <xsl:for-each select="....">
     <xsl:value-of select="."/>
  </xsl:for-each>
</xsl:variable>

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> 
> Kind regards
> 
> Simon
> 
> 
> [code]
> <!--
> <xsl:for-each select="ROW/TIMESTAMP">
>     <xsl:if test="position() = 1">
>         <xsl:element name="starttime"><xsl:value-of 
> select="." /></xsl:element>
>     </xsl:if>
>     <xsl:if test="position() = last()">
>         <xsl:element name="endtime"><xsl:value-of select="." 
> /></xsl:element>
>     </xsl:if>
> 
>     <xsl:variable name="timestamps" 
> select="concat($timestamps, ./text())" />
> 
>     <xsl:if test="position() != last()">
>         <xsl:variable name="timestamps" 
> select="concat($timestamps, $delim)" />
>     </xsl:if>
>  </xsl:for-each>
> -->
> 
> "Make it idiot proof, and someone
>  will make a better idiot" - Anon
> 
> Institut fuer
> Prozessdatenverarbeitung
> und Elektronik,
> Forschungszentrum Karlsruhe GmbH,
> Postfach 3640,
> D-76021 Karlsruhe,
> Germany.
> 
> Tel: (+49)/7247 82-4042
> E-mail : kelly@xxxxxxxxxx
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list