RE: concatenated key

<xsl:if test="some $x in //node/@name satisfies ($x =
$theseChildren)">

I-Lin Kuo, Ann Arbor, MI
Macromedia Certified ColdFusion 5.0 Advanced Developer
Sun Certified Java 2 Programmer
Ann Arbor Java Users Group (http://www.aajug.org)

----Original Message Follows----
From: David.Pawson@xxxxxxxxxxx
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  concatenated key
Date: Wed, 23 Apr 2003 09:06:42 +0100

> Given a node, I'm trying to identify/pull out those nodes in
> the document
> having the same set of identically named child nodes. For
> example, given the
> node Alpha in the following, I'd like to pull out the  "Alpha2" node.
>
> <node name="Alpha">
>   <node name="a"/>
>   <node name="b"/>
> </node>
> <node name="roman">
>   <node name="i"/>
>   <node name="ii"/>
> </node>
> <node name="Alpha2">
>   <node name="a"/>
>   <node name="b"/>
> </node>

Beating Jeni to it for once :-)
In xslt 2 this is

<xsl:template match="node">
  <xsl:variable name="theseChildren" select="node/@name"/>
  <xsl:if test="some $x in ../node/node/@name satisfies ($x =
$theseChildren)">
      <xsl:variable name="this" select="generate-id()"/>
      (I am <xsl:value-of select="@name"/>)
    <xsl:for-each select="../node">
      <xsl:if test="(node/@name = $theseChildren ) and not(generate-id() =
$this)">
        Match at         <xsl:value-of select="position()"/>  <br />

      </xsl:if>
  </xsl:for-each>
</xsl:if>
</xsl:template>