Re: use of xsl:key in cross-referencing

<xsl:key name="QuestionnaireKey"
 match="row[count(cell)=3]/cell[2]"
 use="."/>

<xsl:key name="QuestionnaireKey"
 match="row[count(cell)=2]/cell[1]"
 use="."/>

<row row="17">
  <cell column="1">Questionnaire B</cell>
  <cell column="2">QB</cell>
  <cell column="3">Questionnaire B, empty with no questions</cell>
</row>

<row row="28">
  <cell column="1">QA</cell>
  <cell column="2">Questionnaire A, Question 2</cell>
</row>

<xsl:template match="/">
  <xsl:apply-templates
    select="//cell[key('QuestionnaireKey',.) and
                   count(.|key('QuestionnaireKey',.)[1])=1 ]"/>
</xsl:template>

Cheers,
Wendell

Hi, Wendell:

Thanks for the idea of define two keys for the two
groups with the same name but different "use" value,
but I was unable to find anything in regard to it at
Jenni's website, xsl-list archive (using keywords "two
key;same name;") or google web/group.  I did some
thinking myself and still don't see how that works.
Following is an example, having rows 10-19 being the
first group (Questionnaire) and 20-29 being the second
group (Question):
<range>
<row row="16">
        <cell column="1">Questionnaire A</cell>
        <cell column="2">QA</cell>
        <cell column="3">Questionnaire A, two
questions</cell>
</row>
<row row="17">
        <cell column="1">Questionnaire B</cell>
        <cell column="2">QB</cell>
        <cell column="3">Questionnaire B, empty with no
questions</cell>
</row>

<row row="27">
        <cell column="1">QA</cell>
        <cell column="2">Questionnaire A, Question 1<cell>
</row>
<row row="28">
        <cell column="1">QA</cell>
        <cell column="2">Questionnaire A, Question 2</cell>
</row>
<row row="29">
        <cell column="1">QC</cell>
        <cell column="2">Questionnaire C, Question 1</cell>
</row>
</range>

In this case, questionnaire QA has two questions, QB
is only referred in the 1st group and QC is only
referred in the 2nd group.  What I need is to be able
to process each of QA/QB/QC.

To define two keys for the two groups with the same
name but different "use":
<xsl:key name="QuestionnaireKey" match=//row[@row &lt;
20]" use="string(cell[@column=2])"/>
<xsl:key name="QuestionnaireKey" match=//row[@row &gt;
20]" use="string(cell[@column=1])"/>

Use Muenchian method to process each just once, for
the 2nd group:
<xsl:apply-templates select="//row[@row &gt; 20 and
@row &lt; 30][count(.|key('QuestionnaireKey',
string(cell[@column=1]))[1]) = 1]"/>
but this will miss questionnaire QC.

I guess to take advantage of the combined key, I need
to do select on all rows, like:
<xsl:apply-templates
select="//row[count(.|key('QuestionnaireKey',
string(cell[@column=1]))[1]) = 1]"/>
Would the above work?  If so, how can I tell if the
row being processed is from group 1 (Questionnaire) or
2 (Question)?

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