RE: Get Position of Node in Ancestor Context

You are following the well-trodden mistake of thinking "I want the
position of something, therefore I need the position() function".

The position() function gives you the position of a node in the list of
nodes you are currenly processing.

If you want the position of a node relative to related nodes in the same
tree, there are two ways of doing it: xsl:number, and count(). For
example, count(preceding::*). In this example, xsl:number is a better
bet. 

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Ted Stresen-Reuter
> Sent: 10 March 2003 15:21
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Get Position of Node in Ancestor Context
> 
> 
> Hi,
> 
> I'm trying to get the position of the current node in the 
> context of an 
> ancestor.
> 
> For example, I have a form element that has a number of children 
> elements, including non-form elements (such as P and DIV 
> elements). I'm 
> trying to retrieve the position of an INPUT element relative to the 
> parent FORM element, but not taking into account any non-form 
> elements 
> (such as P and DIV elements).
> 
> Currently I have a template that matches "input | select | textarea" 
> but because they occur in the context of a TD element, position() 
> returns "1". I've tried using <xsl:value-of 
> select="ancestor::form/*/*[position()]" />, but this just isn't doing 
> the trick.
> 
> Any suggestions how I can get the position of the current element 
> relative to a parent form element?
> 
> Ted Stresen-Reuter
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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