RE: Xpath patern question

Hi Helder.

Try this:
<xsl:template match="date">
 <!-- this will remove spaces and lf. It also translates '-' to '/' so
you can use only one test -->
 <xsl:variable name="dt" select="translate(normalize-space(.),'-
','/')"/>
 <!-- the date format used is: dd/mm/yyyy -->
 <!-- the day is easy :) -->
 <xsl:variable name="d" select="substring-before($dt,'/')"/>
 <!-- the month is like the day but we'll have to extract first the
'dd/' part -->
 <xsl:variable name="m"
select="substring-before(substring($dt,string-length($d) + 2),'/')"/>
 <!-- to extract the year we can use the same method used for the month
but with substring-after -->
 <xsl:variable name="a"
select="substring-after(substring($dt,string-length($d) + 2),'/')"/>
 <!-- this is just for display the values, here you'll have the tree
variable $d = day, $m = month and $a = year -->
  <Data>
   <Dia><xsl:value-of select="$d"/></Dia>
   <Mes><xsl:value-of select="$m"/></Mes>
   <Ano><xsl:value-of select="$a"/></Ano>
  </Data>
 </xsl:template>

This template works with the following xml, you'll have to change It to
your needs
<doc>
 <date>1/1/2002</date>
 <date>10/12/2003</date>
 <date>12/3/2001</date>
</doc>

Hope that this helps you

> -----Mensagem original-----
> De: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] Em nome de Hélder Sousa
> Enviada: segunda-feira, 10 de Março de 2003 17:35
> Para: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Assunto: RE:  Xpath patern question
> 
> 
> I had think about that solution but my date can be like 
> "1/1/2003" and I can't change it to " 1/ 1/2003".. So that 
> doesn't work. I can put some more conditions in [...] but in 
> this case it's better to use the script.. The regular 
> expression would be the best way.. Tks anyway :)
> 
> 
(...)
 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list