RE: xsl- Transforming to HTML table with two entries i

Hip hei!

> Let's say I hae the following XML
> <fields>
> 	<field>
> 		<name>Field 1</name>
> 		<value>Value 1</value>
> 	</field>
> 	<field>
> 		<name>Field 2</name>
> 		<value>Value 2</value>
> 	</field>
> 	<field>
> 		<name>Field 3</name>
> 		<value>Value 3</value>
> 	</field>
> 	<field>
> 		<name>Field 4</name>
> 		<value>Value 4</value>
> 	</field>
> </fields>
> and I want the html table output (using XSL transfomration) to be :
> <table>
> <tr>
> <td>Field 1</td>
> <td>Value 1</td>
> <td>Field 2</td>
> <td>Value 2</td>
> </tr>
> <tr>
> <td>Field 3</td>
> <td>Value 3</td>
> <td>Field 4</td>
> <td>Value 4</td>
> </tr>
> </table>
> 
> My problem is creating the mechnism that puts 2 (istead of 1 which is
> simple and easy) "fields" in one row (tr element)

It's a grouping problem, and there's most probably an entry for it in the FAQ. Anyhow,

<xsl:template match="fields">
  <table>
    <xsl:for-each select="field[position() mod 2 = 1]">
      <tr>
        <xsl:for-each select="./* | following-sibling::field[1]/* ">
          <td>
            <xsl:value-of select="." />
          </td>
        </xsl:for-each>
      </tr>
    </xsl:for-each>
  </table>
</xsl:template>

should do the trick.

Cheers,

Jarno - Delerium: Heaven's Earth (Matt Darey remix)

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