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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: generate full xpath name to an attribute?
At 02:57 PM 3/31/03 +0200, you wrote:
Ray Tayek wrote:hi, i need to generate the full xpath name (location) for attributes in the following xsl (see below). yikes! - looks like the simplest way is to have: <xsl:template match="name">
<xsl:for-each select="ancestor-of-self::*">
<xsl:value-of select="name()" /><xsl:text>/</xsl:text>
</xsl:for-each>
<xsl:value-of select="." />
</xsl:template>in *every* atribute of the document. i suppose one could build up a variable that had the path to the current node, but that sees like an awful lot of work. i will try this out though. one woul think that the parser would just know this and could emit it in a canonical form. hard to believe that there is no function call to do this. thanks for your prompt assistance. --- ray tayek http://tayek.com/ actively seeking mentoring or telecommuting work vice chair orange county java users group http://www.ocjug.org/ hate spam? http://samspade.org/ssw/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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