RE: how to insert the *complete* content of a node

I too have hit this problem, perhaps I have overlooked something here
but an xs:copy-of or a deep copy will return an exact copy:

Given an input of:
<mytag>blabla <foo>foo text</foo> other stuff </mytag>
an xsl:copy-of will result in:
<mytag>blabla <foo>foo text</foo> other stuff </mytag>

ie , the same, which is not necessarily what you want, ie you may want:

<peter name="yes" att="yes">
blabla <foo>foo text</foo> other stuff
</peter>

so how would I get this, ie what would the xsl be?

Regards Peewee
-----Original Message-----
From: Robert P. J. Day [mailto:rpjday@xxxxxxxxxxxxxx] 
Sent: 21 March 2003 14:07
To: xsl list
Cc: danilo
Subject: Re:  how to insert the *complete* content of a node

On Fri, 21 Mar 2003, Jeni Tennison wrote:

> Hi Danilo,
> 
> > I have some node that may contain *any* text, including
xml/html-like
> > text.
> > I mean something like:
> >
> > <mytag>blabla <foo>foo text</foo> other stuff </mytag>
> >
> > I have to produce the complete content of the mytag tag:
> >
> > blabla <foo>foo text</foo> other stuff 
> 
> Use <xsl:copy-of> and select all the children of the <mytag> element
> using the node() node test (which matches any node, including elements
> and attributes):
> 
>   <xsl:copy-of select="mytag/node()" />
> 
> <xsl:copy-of> gives you an exact copy of the nodes.

uh oh ... i'm confused again.  i thought "node()" explicitly
did *not* match attribute nodes, but only

1) elements
2) text
3) comments
4) processing instructions

was the original poster concerned about attributes as well?

rday


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