RE: Wrapping consecutive similar elements inside a new

How about this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml"/>
  
  <xsl:template match="/">
    <xsl:apply-templates/>
  </xsl:template>
  
  <xsl:template match="doc">
    <doc>
      <xsl:apply-templates select="p[not(span[substring(text(),1,1) =
'-'])]"/>
    </doc>
  </xsl:template>
  
  <xsl:template match="p[not(span[substring(text(),1,1) = '-'])]">
    <xsl:copy-of select="."/>
    <xsl:if test="following-sibling::p[span[substring(text(),1,1) = '-']]">
      <ul>
        <xsl:for-each
select="following-sibling::p[span[substring(text(),1,1) = '-']][
                count(preceding-sibling::p[not(span[substring(text(),1,1) =
'-'])][1] | current()) = 1]">
          <xsl:apply-templates select="."/>
        </xsl:for-each>
      </ul>
    </xsl:if>
  </xsl:template>
  
  <xsl:template match="p[span[substring(text(),1,1) = '-']]">
    <li><xsl:value-of select="text()"/></li>
  </xsl:template>
</xsl:stylesheet>

-----Original Message-----
From: Graham Hannington [mailto:Ghannington@xxxxxxx]
Sent: 14 February 2003 11:10
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Wrapping consecutive similar elements inside a new parent
element


I'm cleaning up HTML exported from Word documents.  First, I run Tidy again
the exported HTML, to convert it to well-formed XHTML, then I transform it
with my own XSLT stylesheet.

I need to convert (this is slightly simplified):


<p>Some paragraph that does not begin with a span element whose first
character is a hyphen.</p>
<p><span>-</span>List item</p>
<p><span>-</span>List item</p>
<p><span>-</span>List item</p>
<p><span>-</span>List item</p>
<p>Some paragraph that does not begin with a span element whose first
character is a hyphen.</p>
<p><span>-</span>List item</p>
<p><span>-</span>List item</p>
<p><span>-</span>List item</p>
<p><span>-</span>List item</p>
<p>Some paragraph that does not begin with a span element whose first
character is a hyphen.</p>


into this:


<p>Some paragraph that does not begin with a span element whose first
character is a hyphen.</p>
<ul>
<li>List item</li>
<li>List item</li>
<li>List item</li>
<li>List item</li>
</ul>
<p>Some paragraph that does not begin with a span element whose first
character is a hyphen.</p>
<ul>
<li>List item</li>
<li>List item</li>
<li>List item</li>
<li>List item</li>
</ul>
<p>Some paragraph that does not begin with a span element whose first
character is a hyphen.</p>


I'm afraid my attempts at this have been truly pitiful:


	<xsl:template match="p[starts-with(span[1], '-')]">

		<xsl:if
test="not(starts-with(preceding-sibling::p[1]/span[1], '-'))">
			<xsl:text>&lt;ul&gt;</xsl:text>
		</xsl:if>

		<li>
			<xsl:apply-templates />
		</li>

		<xsl:if
test="not(starts-with(following-sibling::p[1]/span[1], '-'))">
			<xsl:text>&lt;/ul&gt;</xsl:text>
		</xsl:if>
	</xsl:template>


I know, I know: those <xsl:text>&lt;ul&gt;</xsl:text> bits are a joke, they
don't produce the <ul> parent element.

I've tried writing a template that uses <xsl:for-each>, but that ends up
grabbing all following-sibling <p> elements that begin with <span>-</span>.
I don't know how to stop the <xsl:for-each> at the first non-matching <p>
element.

Can anyone throw me an XSLT pearl?

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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