RE: Problems copying elements recursively.

Thanks Tom. I am sorry I was not very clear in the
question. It is true that I am trying to display the
angle brackets, etc. Here is what i am doing: I am
transforming the nodetree into a table to display as
html. However, I am also trying to show the raw xml
for a particular node and all its decendants. The
problem is that the templates i am using does not
traverse the tree recursively. it only shows the node
and its immediate children...maybe my xpath statement
is incorrect. 

--- "Passin, Tom" <tpassin@xxxxxxxxxxxx> wrote:
> [ Imrran Wahid ]
> > 
> > I've been trying with this piece for a while but
> still
> > cannot get it right.
> > 
> > I am trying to copy a certain node-tree from the
> xml
> > document via xsl style sheet. Basically i would
> like
> > the output to be an xml representation of the node
> > tree.
> > 
> 
> 1)  If you just want to copy it, just use
> xsl:copy-of to copy the whole
> nodeset of interest.
> 
> 2) It appears you are trying to build up elements by
> inserting "<" and
> ">" signs (example: "<xsl:text></</xsl:text>").  DO
> NOT EVEN THINK OF
> DOING THIS.  Plus, you do not need to do it since
> xslt will do what you
> want (but you have to explain it clearly first). 
> With xslt, you build a
> tree first, and then the angle brackets get put in
> by the serializer
> when you serialize the tree to the output.  Attempts
> to circumvent this
> process will tend to get you in trouble, and even
> when they work lead to
> misunderstanding of how the xslt system is designed
> to work. (Look in
> the FAQs for "disable-output-escaping" for more on
> this).
> 
> If you want to create an element with a name
> extracted from the source,
> you can use xsl:element or, if you already know the
> name, just write the
> whole element with literal tags:
> 
> <name1><xsl:value-of select='theContent'/></name1>
> 
> for example.
> 
> Cheers,
> 
> Tom P
>  
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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