RE: Can I test the name of the current element?

Using a mode on the apply-templates (and templates) or a passed parameter would be my suggestion

<xsl:template match="Line">...
<xsl:template match="Line" mode="full">...

<xsl:template match ...
...
<xsl:apply-templates select="Line" />
...
<xsl:apply-templates select="Line" mode="full"/>
...
</xsl:template>

That said the literal answer to your question is to use "name()='Line'"

HTH,

Ken Ross
Ph: +61 7 32359370
Mob: +61 (0)419 772299
Email: Ken.Ross@xxxxxxxxxxxxxx


-----Original Message-----
From: Adrian [mailto:a.hobson@xxxxxxxxxxxxxxxxxxx]
Sent: Friday, 31 January 2003 9:02 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Can I test the name of the current element?


I am trying to test the name of the current element as shown below.  I know
what I have doesn't work, but it gives an idea of what I am trying to do.
My apologies if this is in a faq somewhere, I had no luck finding a
solution there.

Thanks for any suggestions
Adrian

Simplified version of the XML file:
<CoordGeom>
  <Line/>
  <Line/>
  <Curve/>
  <Line/>
</CoordGeom>


I am already processing the Line and Curve elements using an apply-templates:
<xsl:template match="Line">
<xsl:template match="Curve">

However I need to process them a second time differently:
<xsl:for-each select="CoordGeom/*">
  <xsl:if test="position()=1">
    M <xsl:call-template name="getStart" />
  </xsl:if>
  <xsl:choose>
    <xsl:when test=".=Line"> <!-- something like this -->
      L
    </xsl:when>
    <xsl:when test=".=Curve"> <!-- something like this -->
      A ...
    </xsl:when>
  </xsl:choose>
  <xsl:call-template name="getEnd" />
</xsl:for-each>



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