RE: closing a template inside a table, forbidden?

Yes.

XSLT documents must be well-formed XML.

What is it supposed to do?

--
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> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Hubert Holtz
> Sent: Saturday, January 04, 2003 2:53 PM
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  closing a template inside a table, forbidden?
> 
> 
> Hy,
> 
> is this forbidden ?
> 
> -----CODE-----
> 
> <xsl:template match="article">
> <table>
> ...
>  
> </table>	
> 	<!-- ************SECT1 PROCESSING CONTENT ************** -->
> 		
> 		<table width="610" height="48" cellpadding="0" 
> cellspacing="0" border="0" id="sectBackground">
> 		
> 		<xsl:apply-templates select="./title[@lang= $lang]"/>
> 		<xsl:apply-templates select="sect1[@lang = $lang or 
> not(@lang)]"/>
> 
>   </xsl:template>
> 		
> 		<xsl:template match="article/sect1[@lang= $lang or 
> not(@lang)]">
> 		 
> 		 		  
> 		 		  <xsl:apply-templates/>
> 
> 		</table>
> 
> ----CODE----
> 
> I get the following error:
> 
> The element type "table" must be terminated by the matching end-tag "".
> 
> description org.apache.cocoon.ProcessingException: Exception in 
> creating Transform Handler: org.xml.sax.SAXParseException: The 
> element type "table" must be terminated by the matching end-tag "".
> 
> And if it is forbidden, why?
> 
> Thanks.
> Steve
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list