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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Transforming XML to HTML Table
Nick Foster wrote:
No it's not a typo, the <sample> nodes may appear in any order within eachYou don't understand. In your example first row contains of "sample 1", but second one contains "Sample 1" (note case). That's why label=current()/label doesn't work. If you change "sample 1" to "Sample 1" it works. Thought: Is it possible to do a sort within each row so that they are all in the same order, alphabetical order perhaps? Sure. Something like <xsl:for-each select="samples"> <xsl:sort data-type="text" select="label"/> <TD> <xsl:value-of select="displayval"/> </TD> </xsl:for-each> -- Oleg Tkachenko eXperanto team Multiconn Technologies, Israel XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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