passing in XSL parameters using Saxon

Hi There,
hopefully a simple one - can you see anything wrong with this syntax? It's
driving me up the wall! I am trying to do a command line transformation
using Saxon, passing in a parameter of a filename, and the Saxon parser
states I am using a bad param=value pair, yet as far as I can see, my
command line is using the correct syntax. I am in the correct dir, with the
correct filenames on the command line (in windows).


my input is essentially -o outputfile.xsl xmlToTransformOn.xml
Stylesheet.xsl param=value as per the instructions with Saxon.
See below cut and pasted directly unedited from the dos prompt):

-----------cut n'paste from DOS--------------------------
java -jar C:\java\saxon7-1\saxon7.jar -o test_transformer.xsl
disch-template.xml generator.xsl mapping-file=mappings-discharge.xml
Bad param=value pair on command line
SAXON
Usage:  java net.sf.saxon.Transform [options] source-doc style-doc
{param=value}...
Options:
  -a              Use xml-stylesheet PI, not style-doc argument
  -ds             Use standard tree data structure
  -dt             Use tinytree data structure (default)
  -o filename     Send output to named file or directory
  -m classname    Use specified Emitter class for xsl:message output
  -r classname    Use specified URIResolver class
  -t              Display version and timing information
  -T              Set standard TraceListener
  -TL classname   Set a specific TraceListener
  -u              Names are URLs not filenames
  -w0             Recover silently from recoverable errors
  -w1             Report recoverable errors and continue (default)
  -w2             Treat recoverable errors as fatal
  -x classname    Use specified SAX parser for source file
  -y classname    Use specified SAX parser for stylesheet
  -?              Display this message
---------------end cut n' paste---------------------

Am I doing anything blatently wrong? :) Thanks for your comments,
Alistair

Alistair Power
Research Consultant

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