Re: Testing the name of parent node

Hello all,

I think this is trivial, but I can't seem to find how to do it:

I am in a node <a...> which can have any number of parents or childs of the same type. I want to know if the node I have in hand is the topmost <a...>.

<xsl:if test="not(ancestor::a)">
  no a above me in the tree
</xsl:if>

<xsl:if test="not(ancestor::*[name() = 'a'])">
  the same here
</xsl:if>

I tried looking at the name() funktion, but the explanation was not very clear to me (Michael Kay's book, 2nd edition), and I don't know if this is the right track at all.

I really would appreciate some pointers.

Thank you
Ragulf Pickaxe :)