RE: xsl:attribute problem

The output you are trying to achieve is not well-formed HTML, so the
only way you can construct it with the HTML output method is to use
disable-output-escaping.

The <?---?> thing is not a processing instruction (because PIs can't
occur inside attributes); if it were a PI, you would create it using
xsl:processing-instruction, not xsl:pi.

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx 

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Jens Laufer
> Sent: 02 December 2002 10:58
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  xsl:attribute problem
> 
> 
> Hi all,
> I need to solve this problem:
> I want to create this output from a XML-source and a XSL-stylesheet:
> 
> 
> <---snippet---!>
> <a href="mailto: <?php echo $email?>"><?php echo $email?></a> 
> <---snippet---!>
> 
> 
> I am using this XSL-stylesheet:
> <---snippet---!>
> <?xml version="1.0" encoding="iso-8859-1"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> version="1.0">
> 
> 
>   <xsl:output method="html" indent="yes"/>
> 
> 
>   <xsl:template match="/document">
>      <a>
>       <xsl:attribute name="href">mailto:<xsl:apply-templates 
> select="email"/></xsl:attribute>
>       <xsl:apply-templates select="email"/>
>      </a>
>   </xsl:template>
> 
> 
>  <xsl:template match='email'>
>   <xsl:apply-templates/>
>  </xsl:template>
> 
> 
>  <xsl:template match='*|@*'>
>     <xsl:copy>
>         <xsl:apply-templates select='node()|@*'/>
>     </xsl:copy>
>  </xsl:template>
> 
> 
> </xsl:stylesheet>
> <---snippet---!>
> 
> 
> I tried this XML to get that output: 
> ======================================================================
> XML:
> 
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email><xsl:pi value="php">echo $email</xsl:pi></email> </document>
> 
> 
> 
> I get this error:
> java.io.IOException: /home/jens/test/test.xsl:7: element 
> `xsl:pi' is not 
> allowed inside attribute `href'.
> 
> 
> ================================================================
> XML:
> 
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email><script language="php">echo $email</script></email> 
> </document>
> 
> 
> I get this error:
> java.io.IOException: /home/jens/test/test.xsl:7: element 
> `script' is not 
> allowed inside attribute `href'.
> 
> 
> =================================================================
> XML:
> 
> 
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email><?php echo $email ?></email>
> </document>
> 
> 
> I get this output:
> 
> 
> <a href="mailto:";></a>
> 
> 
> =================================================================
> XML:
> <?xml version="1.0" encoding="iso-8859-1"?>
> <document>
>   <email>&lt;?php echo $email ?&lt;</email>
> 
> 
> I get this output:
> 
> 
> <a href="mailto:<?php echo $email ?&lt;">&lt;?php echo $email 
> ?&lt;</a> 
> ==================================================================
> I don't really know how to solve that and I am struggling 
> around with it since  
> a while now...
> 
> 
> Actually I don't want to change the stylesheet too much, 
> because with the 
> current stylesheet it should be possible to swap quickly 
> technologies: You just change e.g. <?php echo $test?> into 
> <%=test%> and you can use jsp... So there should be no 
> "technologiy" infromation in the stylesheet.
> 
> 
> I think especially the attributes are making a lot of 
> problems... Any ideas? Thanks in advance! Jens
> 
> 
> 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


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