Re: Generic XSLT Sorting Template

I am trying to find a way to create a generic xsl sorting function that
takes 5 parameters, which are the names of the nodes to sort.

I dont understand how to pass parameters to an xsl stylesheet, but basically
i just want a simple sorting function that sorts the xml and returns a
sorted version of the xml using xsl:copy.

So far this is what i got:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

 <xsl:template name="GenericSort">
    <!-- The sort fields -->
    <xsl:param name="SortField0" select="" />

You should get an error here -------------^^
("missing argument")
Change it to select="''", same for the rest.

    <xsl:param name="SortField1" select="" />
    <xsl:param name="SortField2" select="" />
    <xsl:param name="SortField3" select="" />
    <xsl:param name="SortField4" select="" />

<xsl:copy >

      <xsl:apply-templates>
        <xsl:sort select="$SortField0" />

        <xsl:sort select="$SortField1" />
        <xsl:sort select="$SortField2" />
        <xsl:sort select="$SortField3" />
        <xsl:sort select="$SortField4" />
      </xsl:apply-templates>
    </xsl:copy>
 </xsl:template>

</xsl:stylesheet>

i want the first sort field
(sortfield0) to sort on the global node-set (ancestor::*[next-sibling()]) ??