Re: sorting based on a variable

Thanx this one works.

- Kasper
----- Original Message ----- 
From: "Michael Kay" <michael.h.kay@xxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, November 12, 2002 4:31 PM
Subject: RE:  sorting based on a variable


> 
> try data[number($column)]
> 
> Perhaps your $column variable is a string or a result tree fragment, not
> a number. You didn't show us its declaration.
> 
> Michael Kay
> Software AG
> home: Michael.H.Kay@xxxxxxxxxxxx
> work: Michael.Kay@xxxxxxxxxxxxxx 
> 
> > -----Original Message-----
> > From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> > [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> > Kasper Nielsen
> > Sent: 12 November 2002 14:34
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject:  sorting based on a variable
> > 
> > 
> > hi (another question)
> > 
> > lets say I want to some data for the $column data-column
> > 
> > <projects>
> >   <project name="a">
> >     <data> 1237</data>
> >     <data> 1234</data>
> >     <data> 1235</data>
> >     <data> 1236</data>
> >   </project>
> >   <project name="b">
> >     <data> 12</data>
> >     <data> 41234</data>
> >     <data> 51235</data>
> >     <data> 71236</data>
> >   </project>
> >   <project name="c">
> >     <data> 1</data>
> >     <data> 41234</data>
> >     <data> 51235</data>
> >     <data> 71236</data>
> >   </project>
> > </projects>
> > 
> > so if $column=1 then it would sort them into {project 
> > name="c", project name="b", project name="a"} however i've 
> > tried <xsl:for-each select="projects/project">
> >     <xsl:sort select="./data[$column]" data-type="number"/>
> > but it doesn't work?
> > however if just use something like
> >     <xsl:sort select="./data[1]" data-type="number"/> it works fine
> > 
> > anyone can tell me what im doing wrong?
> > 
> > regards
> >   Kasper Nielsen
> > 
> > 
> >  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> > 
> 
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 


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