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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: exsl:node-set behaviour with variables
> Hi,
> What happens when a value of a variable is passed to
> exsl:node-set() ? That is, suppose you have the following XSL
> fragment:
>
> <xsl:variable name="nodes">
> <nodes>
> <node>node 1</node>
> <node>node 2</node>
> <node>node 3</node>
> </nodes>
> </xsl:variable>
>
> Name: <xsl:value-of select="local-name(exsl:node-set($nodes))" />
>
> The result I expect is:
>
> Name: nodes
exsl:node-set() returns the root node, which is the parent of the
<nodes> element, and which has no name.
>
> But, with libxslt 1.0.22 processor, I got:
>
> Name: fake node libxslt
I would expect to see an empty string.
>
> To get what I want, I have to write:
>
> Name: <xsl:value-of select="local-name(exsl:node-set($nodes)/*)" />
>
> really tedious!!!
>
What would you expect to get if the variable was
> <xsl:variable name="nodes">
<a/>
> <nodes>
> <node>node 1</node>
> <node>node 2</node>
> <node>node 3</node>
> </nodes>
<z/>
> </xsl:variable>
?
Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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