Re: [xsl-fo] generating the correct number of columns

My question is: if I have a number (say "8"), how do I loop through to
generate 8 times the line : <fo:table-column column-width="2cm"/> ?


<xsl:for-each select="//*[position() &lt;= 8]">
<fo:table-column column-width="2cm"/> 
</xsl:for-each>

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