RE: How a node value of an external xml file?
Hi Iris > Problem is that I want to get translated data from my external file > (translations.xml) in my xsl. I want to do this by passing > the founded > parameters (txtNode & txtLang), but that didn't work. > (cfr. <xsl:value-of select="$resource/$txtNode/$txtLang"/>) > When I pass my values without parameters it works! (cfr. > <xsl:value-of > select="$resource/AddressTitle/EN"/>) > > How can I pass my parameters to get the correct node value of my file > Translations.xml ??? you can't use $parameters in XPath expressions like that. $txtNode contains a string - would you expect to be able to do "$resource/'AddressTitle'/'EN'? You can use a predicate though: select="$resource/*[local-name()=$txtNode]/*[local-name()=$txtLang]" It's bad xml to encode information in the name of elements. Instead of <Resource> <AddressTitle> <EN>Customer: </EN> <NL>Klant: </NL> <FR>Client: </FR> </AddressTitle> </Resource> why not make the type of resource (Address Title, EN / NL / FR) into an attribute? wotcher, Tom XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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