[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

Re: backwards tree-traversal algorithm?

Subject: Re: backwards tree-traversal algorithm?
From: Stephen Cunliffe <scunliffe@xxxxxxxxxxxxxxxxxx>
Date: Wed, 23 Oct 2002 10:51:55 -0400
walk the tree
This isn't quite what you want, but it may help...

Define this template first:
<xsl:template match="*" mode="whereAmI">
<xsl:param name="location"/>
<xsl:choose>
<xsl:when test="name(.) = 'root'">Location = <xsl:value-of select="name(.)"/> / <xsl:value-of select="$location"/> </xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="parent::*" mode="whereAmI">
<xsl:with-param name="location"><xsl:value-of select="name(.)"/><xsl:if test="string($location) != ''"> / <xsl:value-of select="$location"/></xsl:if></xsl:with-param>
</xsl:apply-templates>
</xsl:otherwise>
</xsl:choose>
</xsl:template>


Then, when you need to know "where you are", call this one.

<xsl:apply-templates select="." mode="whereAmI"/>


It should return *if* 'inside' <c/> (with your data)...


"Location = root / a / b / c"

Cheers,

Steve

On 10/23/02 10:22 AM, jm3 wrote::

hello, having some trouble making this work: within my stylesheet,
i have selected a node somewhere in the midst of the document tree,
several nested elements deep.  what i would like to do is, given
this node N (at arbitrary depth), walk *back* up the document tree
hierarchy, element by element, printing the successive parent elements
(technically, printing each element's "name" @ribute).

so with node N being <c> and the following document:

<root>
 <a>
	  <b>
		  <c/>
		</b>
		<d/>
		<e/>
	</a>
</root>

i want to print: b, a, root.

my pseudocode was along the lines of:

current = node
while current != root
 current = ../
	print current/@name

seems simple.

recursive templates seemed like the way to do this in xsl, but i
can't get this to do anything, apparently because the processor i'm
using (sablotron 0.90) won't let me use XPath on the node set i am
passing with call-template (as a param) because it's "not a node-set".

so i guess i have two questions:

1. what is the best algorithm/approach to walk back up the parent:: tree, printing each element?

2. does sabcmd not have a node-set() function? is this what's stopping me?

(if it helps, the stylesheet will know what depth level the current
node is at, and the unique @name attribute of each parent element.)

jm3 / john manoogian III / http://jm3.net / jm3@xxxxxxx

> > > http://jm3.net/linkworld < < <

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list







XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list



Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.