RE: Sorting on a transformed string?

Hi,

can you change the XML? YOu could do it pretty easily if the structure was
something like:

<Member name="System">
   <Member name="Caption">
      <Member name="Insert">

      </Member>
   </Member>
   <Member name="Collections">
      <Member name="ICollection">
         <Member name="Count">

         </Member>
      </Member>
   </Member>
</Member>


> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Scott Bronson
> Sent: Saturday, October 26, 2002 9:58 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Sorting on a transformed string?
>
>
> Hello.  A sort problem is stumping me right now.  I've got the following
> nodes:
>
>     <Member name="CreateInstance">
>     <Member name="System.Caption.Insert">
>     <Member name="System.Collections.ICollection.Count"
>
> I'd like to sort them by name, without leading namespace:
>
>     Count, CreateInstance, Insert
>
> Then I'd like to output them, WITH the namespace:
>
>     System.Collections.ICollection.Count
>     CreateInstance
>     System.Caption.Insert
>
> Normally, I use leaf-name (below) to trim the namespace.  However, I
> suspect it's impossible to get sort to use a named template, and I
> haven't figured out any other way of figuring out the leaf name.
>
> Is possible to sort on the leaf name?  Is it possible in XML 1.0?  :)
>
> Thank you!
>
>     - Scott
>
>
>
> <xsl:template name="leaf-name">
>   <xsl:param name="string"/>
>   <xsl:choose>
>     <xsl:when test="substring-after($string,'.')">
>       <xsl:call-template name="leaf-name">
>         <xsl:with-param name="string"
> select="substring-after($string,'.')"/>
>       </xsl:call-template>
>     </xsl:when>
>     <xsl:otherwise>
>       <xsl:value-of select="$string"/>
>     </xsl:otherwise>
>   </xsl:choose>
> </xsl:template>
>
>
>
>
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>



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