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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] xsl: display only a specified node...
 hi folks
i'm not able to find a solution for that...and my xsl knowledge isn't that
good, so here's the situation:
XML:
<sequence stype="ondemand" broadcastID="00">
<mark ID="m0001" name="testh" time="0:00:00">
<index>
<chapter lang="en" text="test1"/>
</index>
</mark>
<mark ID="m0002" name="" time="0:00:20" />
<mark ID="m0003" time="0:00:40" />
<mark ID="m0004" time="0:01:00" />
<mark ID="m0005" time="0:01:20">
<index>
<chapter lang="en" text="test2"/>
</index>
</mark>
</sequence>
this xml is used for the data itself and to build up a tree menu structure
like this (that works w/o problems):
frameset
-------------------------------------------------------
tree menu frame details frame
--------------------------- -------------------------
|sequence | | |
| - mark 0:00:00 (m0001) | | |
| - index | | |
| - mark 0:00:20 (m0002) | | |
| - mark 0:00:40 (m0003) | | |
| - mark 0:01:00 (m0004) | | |
| - mark 0:01:20 (m0005) | | |
| - index | | |
--------------------------- -------------------------
functionality:
i click on sequence, and on the details frame the stype and broadcastID
attributes are shown (that works w/o problems).
i click on any mark, and the mark info (id / name / time) is shown in the
details frame. (that works w/o problems)
i click on index under mark (m0001) and ONLY the index, that's belong to
m0001 should be displayed, but i get both...
the one from m0001 and m0005. here's the xsl:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="page"/> i get this from a asp script, so i know which
"tree element" was clicked
<xsl:param name="markid"/> i get this from a asp script, so i know which
mark was clicked
<xsl:template match="/">
...
<body>
<xsl:apply-templates />
</body>
...
</xsl:template>
<xsl:template match="sequence">
<xsl:if test="$page = 'sequence'">
...
<xsl:value-of select="@broadcastID" />
...
</xsl:if>
<xsl:apply-templates />
</xsl:template>
<xsl:template match="mark">
<xsl:if test="$page = 'mark'">
<xsl:if test="@ID=$markid">
...
<xsl:value-of select="@name" />
...
</xsl:if>
</xsl:if>
<xsl:apply-templates />
</xsl:template>
<xsl:template match="index">
<xsl:if test="$page = 'index'">
<xsl:apply-templates/>
</xsl:if>
</xsl:template>
<xsl:template match="chapter">
...
<xsl:value-of select="@text"/>
...
</xsl:template>
the problem is that i can't really "identify" the index... so i can't check
which one the xsl should display
it should only show the info that belongs to the clicked tree-element. and
not all the childs from all the marks
as here in the bad example.
and as always please excuse my poor english...
thanks a lot
Jan M. Krattiger
Software Developer
Unit.Net AG
Thurgauerstrasse 54
CH - 8050 Zurich
Email: jan.krattiger@xxxxxxxx
Web: http://unit.net
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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