Re: removing tab formatting during XSLT?

<!-- identity transformation template -->
<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="text()">
    <xsl:value-of select="normalize-space()"/>
</xsl:template>

Could someone please enlighten me on how I can remove tab formatting from my resulting XML.

Here's an example:

Source XML:

<?xml version="1.0"?>
<A>
	<B att="att">a</B>
	<C>b</C>
	<D>c</D>
</A>

Desired output XML (i.e. the same as input but with all tabs removed):

<?xml version="1.0"?><A><B att="att">a</B><C>b</C><D>c</D></A>

XSLT (which doesn't work):

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="no"/>
	
	<xsl:strip-space elements="*"/>
	
	<xsl:template match="/">
		<xsl:apply-templates/>
	</xsl:template>
	
	<xsl:template match="*">
		<!-- recreate the element -->
		<xsl:element name="{name()}">
			<!-- copy existing attributes-->
			<xsl:for-each select="@*">
				<xsl:copy/>
			</xsl:for-each>
			<xsl:apply-templates/>
		</xsl:element>
	</xsl:template>
	
	<xsl:variable name="tab">nbsp;</xsl:variable>
	
	<xsl:template match="text()">
		<xsl:value-of select="translate(. , $tab , '')"/>
	</xsl:template>

<!-- original attempt
<xsl:template match="text()">
<xsl:value-of select="normalize-space(.)"/>
</xsl:template>
-->
</xsl:stylesheet>

I want to remove the tabs because this significantly reduces the size of the file.

Thanks in advance.

cheers

Malcolm