Re: Sorting Question: Muenchian method? Substring in K

--- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:

> Hi Mark,
> 
> Yes, the use of the Muenchian method to solve your problem is very
> straightforward:
> 
> source xml (the one provided by you, but reshuffled):
> ---------------------------------------------------
> <topics>
>   <topic>Chimpanzee</topic>
>   <topic>Aardvark</topic>
>   <topic>Beetle, Smaller European Elm Bark</topic>
>   <topic>Anteater</topic>
>   <topic>Beetle, American Burying</topic>
> </topics>
> 
> stylesheet:
> ----------
> <xsl:stylesheet version="1.0" 
>  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>  
>   <xsl:output method="text"/>
>   
>   <xsl:variable name="NL" select="'
'"/>
> 
>   <xsl:key name="kTopic" match="topic" use="substring(.,1,1)"/>
> 
>   <xsl:template match="/">
>     <xsl:for-each select="/*/topic
>                               [
>                                generate-id()
>                               =
>                                generate-id(key('kTopic',
>                                                substring(.,1,1) 
>                                                )[1]
>                                            )
>                               ]">
>       <xsl:sort select="substring(.,1,1)"/>
>       
>       <xsl:value-of select="concat($NL, substring(.,1,1))"/>
>       
>       <xsl:for-each select="key('kTopic',substring(.,1,1))">
>         <xsl:value-of select="concat($NL, .)"/>        
>       </xsl:for-each>
>       <xsl:value-of select="$NL"/>
>     </xsl:for-each>
>   </xsl:template>
> </xsl:stylesheet>
> 
> Result:
> -------
> 
> A
> Aardvark
> Anteater
> 
> B
> Beetle, Smaller European Elm Bark
> Beetle, American Burying
> 
> C
> Chimpanzee
> 
> 

Just a minor addition: as they are at the moment, the results are not
sorted, but only grouped by their first letter.

Therefore, in the above code

>       <xsl:for-each select="key('kTopic',substring(.,1,1))">
>         <xsl:value-of select="concat($NL, .)"/>        
>       </xsl:for-each>

should actually be:

       <xsl:for-each select="key('kTopic',substring(.,1,1))">
         <xsl:sort select="."/>
         <xsl:value-of select="concat($NL, .)"/>        
       </xsl:for-each>




=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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