Re: document() loops

From: David Carlisle <davidc@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
CC: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  document() loops
Date: Fri, 13 Sep 2002 10:19:21 +0100

  <xsl:for-each select="document(/univ-xml-list/univ-xml[1])">
  <xsl:variable name = "element-name" select="name(.)"/>
  <xsl:element name="$element-name">

  </xsl:element>
  </xsl:for-each>
  this will create all the elements that are in the first elements..

No it won't as I said before that for-each is iterating over a single node
so it will only create one element, with name equal to teh name of teh
node selected in the xsl:for-each select=" however that node is a
document node, so has name "" so the xsl:eleemnt should generate an
error thatyou are trying to generate an element with an invalid name,
"".

David

_____________________________________________________________________
This message has been checked for all known viruses by Star Internet
delivered through the MessageLabs Virus Scanning Service. For further
information visit http://www.star.net.uk/stats.asp or alternatively call
Star Internet for details on the Virus Scanning Service.

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

_________________________________________________________________
Send and receive Hotmail on your mobile device: http://mobile.msn.com