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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XSLT/XPath help to resolve definition references i
It almost worked, but it put me on the right track.
What you gave me is not working as in your select, in the key function
second argument, the @aRef is not known in this context (this is not an
attribute of the A element. But I was able to achieve what I wanted doing
the following:
<xsl:key name="Crefs" match="C" use="substring-after(@aRef,':')"/>
select="A[count(key('Crefs',@name))>0]/B"
The condition in the select of the A element means any A referenced by at
least one C element.
Thanks a lot for the help.
Thomas
-----Original Message-----
From: TSchutzerWeissmann@xxxxxxxxxxxxxxxx
[mailto:TSchutzerWeissmann@xxxxxxxxxxxxxxxx]
Sent: Wednesday, September 04, 2002 10:41 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE: XSLT/XPath help to resolve definition references in a W
SDL XML fi le
hi Thomas,
> I need some help on pure XSLT/XPath syntax/capabilities. Let's say
> that I have an XML document looking like that:
>
> <root>
> <A name="a1"><B .../></A>
> <A name="a2"><B .../></A>
> <A name="a3"><B .../></A>
> <C aRef="ns1:a1"/>
> <C aRef="ns2:a2"/>
> </root>
>
> I want to be able to select all the B element which are under
> the A elements
> referenced by the C element (the A elements for which a
> C/@aRef attribute
> value, minus the prefix, is equal to the A/@name attribute).
>
Use a key on the C's:
<xsl:key name="CRefs" match="C" use="@aRef"/>
Then this as your path in <root> context.
select="A[@name = key('CRefs',substring-after(@aRef,':'))]/B"
Don't know if it works...
Tom
---
"At the first performance I led the attack in person 33 times.
We had three acclamations, four hilarities, two thrilling movements,
four renewals of applause and two indefinite explosions."
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