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RE: XSLT/XPath help to resolve definition references i

Subject: RE: XSLT/XPath help to resolve definition references in a W SDL XML fi le
From: thomas.cherel@xxxxxxxxxxxxxxxxxxxxx
Date: Wed, 4 Sep 2002 14:47:36 -0400
xslt resolve references
It almost worked, but it put me on the right track.
What you gave me is not working as in your select, in the key function
second argument, the @aRef is not known in this context (this is not an
attribute of the A element. But I was able to achieve what I wanted doing
the following:

<xsl:key name="Crefs" match="C" use="substring-after(@aRef,':')"/>


The condition in the select of the A element means any A referenced by at
least one C element.

Thanks a lot for the help.


-----Original Message-----
From: TSchutzerWeissmann@xxxxxxxxxxxxxxxx
Sent: Wednesday, September 04, 2002 10:41 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  XSLT/XPath help to resolve definition references in a W
SDL XML fi le

hi Thomas,

> I need some help on pure XSLT/XPath syntax/capabilities. Let's say 
> that I have an XML document looking like that:
> <root>
>   <A name="a1"><B .../></A>
>   <A name="a2"><B .../></A>
>   <A name="a3"><B .../></A>
>   <C aRef="ns1:a1"/>
>   <C aRef="ns2:a2"/>
> </root>
> I want to be able to select all the B element which are under
> the A elements
> referenced by the C element (the A elements for which a 
> C/@aRef attribute
> value, minus the prefix, is equal to the A/@name attribute).

Use a key on the C's:

<xsl:key name="CRefs" match="C" use="@aRef"/>

Then this as your path in <root> context.
 select="A[@name = key('CRefs',substring-after(@aRef,':'))]/B"

Don't know if it works...

"At the first performance I led the attack in person 33 times.
We had three acclamations, four hilarities, two thrilling movements,
four renewals of applause and two indefinite explosions."

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