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Re: Re: print out the actual node (NEWBIE)

Subject: Re: Re: print out the actual node (NEWBIE)
From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>
Date: Mon, 16 Sep 2002 15:55:20 +0200
xsl print out
Check out the SHOWTREE free resource in the resource library linked near the top of our home page noted below ... this stylesheet exposes the entire XPath node tree for an arbitrary XML document. The path down to a node is maintained at each level of the tree. I'm not sure what your context is for wanting to display the path, so I'm not sure if this is what you need.

I hope this helps.

................ Ken

At 2002-09-16 15:16 +0200, thomas wrote:
I found a resolution. ugly hack I think...but it works
<xsl:value-of select="name(../../../..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name(../../..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name(../..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name(..)"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="name()"/>

thomas wrote:
Im having problems with my template and I think somehow its related to the node. Is there a way to print out the actual node I'm in?
<a>
<b/>
<c>
<xsl:value-of select="name()"/>
</c>
<d/>
</a>
prints out only "c"
but I need "a/c"
cant find anything.
thanx
le beck


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G. Ken Holman               mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
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