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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Getting the XPath of a node
Dennis wrote:
> Hi All,
>
> Is there any way to get the XPath of a particular
> element and attribute in match template???
>
> Say if I have following XML:
> <Person id="12345">
> <Name>Dennis</Name>
> <Company>Netscape</Company>
> <Address>Mountain View</Address>
> <Email>dennis@xxxxxxxxxxxx</Email>
> </Person>
>
> ----The XSL to print XPath---
> <xsl:template match="Company">
> //Print the XPath of Company as /Person/Company
> </xsl:template>
> More templates corresponding to each element.
>
> How do I do this...any thoughts???
<xsl:for-each select="ancestor::*">
<xsl:value-of select="concat('/',name())"/>
</xsl:for-each>
<xsl:value-of select="concat('/',name())"/>
If the current node is an attribute, change that last '/' to '/@'
- Mike
____________________________________________________________________________
mike j. brown | xml/xslt: http://skew.org/xml/
denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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