Re: Re: sorting on data referenced with document()??

--- "Carter, Will" <WCarter at envestnetpmc dot com> wrote:

Hi,

I have a sorting problem when I use xsl to combine data from 2 xml
files into one html output.

here is my xml file 1 (xml1.xml):
-----------------------
<people>
	<person name="george">
		<cat>cat-zoro</cat>
		<dog>dog-butch</dog>
		<fish>fish-jaws</fish>
	</person>
	<person name="jennifer">
		<cat>cat-felix</cat>
		<dog>dog-fido</dog>
		<fish>fish-moby</fish>
	</person>
	<person name="simon">
		<cat>cat-tom</cat>
		<dog>dog-scooby</dog>
		<fish>fish-conroy</fish>
	</person>
</people>
-----------------------

here is my xml file 2 (xml2.xml):
-----------------------
<people>
	<person name="george">
		<turtle>turtle-greeny</turtle>
	</person>
	<person name="jennifer">
		<turtle>turtle-browny</turtle>
	</person>
	<person name="simon">
		<turtle>turtle-red</turtle>
	</person>
</people>
-----------------------

here is my stylesheet:
-----------------------
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns="http://www.w3.org/tr/REC-html40"; version="2.0">
<xsl:key name="turtleByOwner" match="//turtle" use="../@name" />
<xsl:template match="/">
<table border="1" cellspacing="0" cellpadding="0">
	<xsl:for-each select="people/person">
	<xsl:sort select="cat"/>
	<tr>
		<td colspan="7">Person: <xsl:value-of select="@name"/></td>
	</tr>
	<tr>
		<td><xsl:value-of select="cat"/></td>
		<td><xsl:value-of select="dog"/></td>
		<td><xsl:value-of select="fish"/></td>
		<xsl:variable name="ownerName" select="@name"/>
		<td>
		<xsl:for-each select="document('xml2.xml')">
		<xsl:value-of select="key('turtleByOwner', $ownerName)"
		</xsl:for-each>
		</td>
	</tr>
	</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
-----------------------

this correctly produces (sorted by cat):
-----------------------
Person: jennifer cat-felix dog-fido fish-moby turtle-browny Person: simon cat-tom dog-scooby fish-conroy turtle-red Person: george cat-zoro dog-butch fish-jaws turtle-greeny -----------------------


but I want to sort by turtle (I want this output):
-----------------------
Person: jennifer cat-felix dog-fido fish-moby turtle-browny

Person: george cat-zoro dog-butch fish-jaws turtle-greeny

Person: simon cat-tom dog-scooby fish-conroy turtle-red -----------------------

I changed the sort line to be:
<xsl:sort select="turtle"/>
but it doesn't work, my output is:
-----------------------
Person: george cat-zoro dog-butch fish-jaws turtle-greeny Person: jennifer cat-felix dog-fido fish-moby turtle-browny Person: simon cat-tom dog-scooby fish-conroy turtle-red -----------------------

how can I sort on the turtle column from the document reference?

thanks for any ideas.
will

Hi Will,

Here's a solution, which even does *not* need to produce an
intermediary output in an RTF:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output omit-xml-declaration="yes" indent="yes"/>
  <xsl:template match="/">
    <xsl:variable name="firstRoot" select="."/>
    <xsl:for-each select="document('person2.xml')/people/person">
      <xsl:sort select="turtle"/>
      person: <xsl:value-of select="@name"/>
      <xsl:text>&#xA;</xsl:text>
      <xsl:for-each select="$firstRoot/people/person[@name =
current()/@name]/*">
        <xsl:value-of select="concat(., ' ')"/>
      </xsl:for-each>
      <xsl:for-each select="*">
        <xsl:value-of select="concat(., ' ')"/>
      </xsl:for-each>
    </xsl:for-each>
  </xsl:template>
</xsl:stylesheet>

When applied to your source xml document, the result is:


person: jennifer
cat-felix dog-fido fish-moby turtle-browny person: george
cat-zoro dog-butch fish-jaws turtle-greeny person: simon
cat-tom dog-scooby fish-conroy turtle-red

=====
Cheers,

Dimitre Novatchev.

System Development
VIRBUS AG
Fon  +49(0)341-979-7419
Fax  +49(0)341-979-7409
joerg.heinicke@xxxxxxxxx
www.virbus.de