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Re: My Difficult counting problem

Subject: Re: My Difficult counting problem
From: Mike Brown <mike@xxxxxxxx>
Date: Thu, 22 Aug 2002 16:22:49 -0600 (MDT)
Re:  My Difficult counting problem
Girard Tim-TGIRARD1 wrote:
> hello,
> 
> I need some help doing the following, I can't seem to figure out how to do
> this in XSL
> 
> I need to convert something like this
> <myElement>
>    <foo name="foobar1"/>
>    <foo name="foobar2"/>
>    <foo name="foobar1"/>
>    <foo name="foobar3"/>
>    <foo name="foobar1"/>
>    <foo name="foobar1"/>
>    <foo name="foobar3"/>
> </myElement>
> 
> and the output after running it through the XSL would be
> 
> numberOccurrences[] = {1, 1, 2, 1, 3, 4, 2};
> 
> basically for each foo with a duplicate name you put the occurrence number
> of it in the array at the correct position.

  <xsl:template match="myElement">
    <xsl:text>numberOccurrences[] = {</xsl:text>
    <xsl:for-each select="foo">
      <xsl:value-of select="count(preceding-sibling::foo[@name=current()/@name])+1"/>
      <xsl:if test="position() != last()">, </xsl:if>
    </xsl:for-each>
    <xsl:text>};</xsl:text>
  </xsl:template>

If efficiency is an issue, xsl:key may be of some utility; it would be easy to
set up a key that does the same work as the preceding-sibling business.

   - Mike
____________________________________________________________________________
  mike j. brown                   |  xml/xslt: http://skew.org/xml/
  denver/boulder, colorado, usa   |  resume: http://skew.org/~mike/resume/

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