Re: sort / unsort
Interesting, Could you show me? I couldn't see a way of getting a sorted nodeset into a variable. Wouldn't this approach require that? -- Mike Berrow ----- Original Message ----- From: "Mike Brown" <mike@xxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, August 08, 2002 10:09 PM Subject: Re: sort / unsort Mike Berrow wrote: > Does anyone see a better way? I was going to try the Kay/Becker/Holman technique from the FAQ. http://www.dpawson.co.uk/xsl/sect2/muench.html#d197e74 That is, find the difference between all the nodes and the sorted nodes to get the remaining nodes. No need for generate-id(); count() and != ought to work nicely. - Mike ____________________________________________________________________________ mike j. brown | xml/xslt: http://skew.org/xml/ denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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