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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: How to output partial elements?
Hi Jem,
Something like?...
== XSL ==================================
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="kPreceding-normal" match="record[@type != 'normal']"
use="generate-id(preceding-sibling::record[@type='normal'][1])"/>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="record[@type='normal']">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:copy-of select="node()|key('kPreceding-normal',generate-id())/node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="record[@type!='normal']"/>
</xsl:stylesheet>
== end of XSL =============================
Hope this helps
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger)
http://www.topxml.com/Xselerator
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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