Re: template match question
Hi Sandy, ><xsl:template match="b[c]"/> Should work - when you say 'fails' what happens... and error message or unexpected output? If it is unexpected output then it is possibly due to your stylesheet encountering built-in rule templates (see http://www.w3.org/TR/xslt#built-in-rule ) ><xsl:template match="b[//c]"/> Will match a <b> element whenever there is a <c> anywhere in the XML. Cheers Marrow http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger) http://www.topxml.com/Xselerator -----Original Message----- From: Sandy McArthur <sandymac@xxxxxxx> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Date: 02 August 2002 17:06 Subject: template match question >I'm having trouble figuring out how to have two templates that match the >same element but differ based on if a child elements exists. > >Source fragment: > ><a> > <b> > <c> > foo > </c> > </b> > > <b> > bar > </b> ></a> > >I'm having trouble writing a template match for 'b' when it has a 'c' >element. Here is what seems logical to me but won't work and any little >varriation I come up with fails too: > ><xsl:template match="b[c]"/> > >That form seems logical to me because this at least makes the template >match but how I want it to: > ><xsl:template match="b[//c]"/> > >What am I doing wrong and/or how is my thinking wrong? > >FYI: I'm using the Xalan that comes with the Sun 1.4 JVM on linux. > >Thanks, >Sandy McArthur > > > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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