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RE: <xsl:apply-templates select="not('nodename')"/> ?

Subject: RE: <xsl:apply-templates select="not('nodename')"/> ?
From: "Américo Albuquerque" <aalbuquerque@xxxxxxxxxxxxxxxx>
Date: Tue, 27 Aug 2002 16:25:07 +0100
xsl apply templates select not
Hi Michael!

your third apply-templates is selecting a boolean value (not(...)). you
need to change your xpath to select nodes
something like:
<xsl:apply-templates select="*[not(name()='apple' or

hope that this helps you

-----Original Message-----
From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
[mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Michael
Sent: Tuesday, August 27, 2002 4:02 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  <xsl:apply-templates select="not('nodename')"/> ?

I would like to preferentially list some children ahead of others. I'm
trying to do it like this:

<xsl:apply-templates select="./apple"/>
<xsl:apply-templates select="./orange"/>
<xsl:apply-templates select="not(apple|orange)"/>

... I want for the third line to process all other children. It's not
working that way though. What's the right syntax to achieve this?



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